Optimal. Leaf size=119 \[ -\frac{5 c^3 \tan (e+f x)}{a^2 f}+\frac{5 c^3 \tanh ^{-1}(\sin (e+f x))}{a^2 f}-\frac{10 \tan (e+f x) \left (c^3-c^3 \sec (e+f x)\right )}{3 f \left (a^2 \sec (e+f x)+a^2\right )}+\frac{2 c \tan (e+f x) (c-c \sec (e+f x))^2}{3 f (a \sec (e+f x)+a)^2} \]
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Rubi [A] time = 0.185887, antiderivative size = 119, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 32, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.156, Rules used = {3957, 3787, 3770, 3767, 8} \[ -\frac{5 c^3 \tan (e+f x)}{a^2 f}+\frac{5 c^3 \tanh ^{-1}(\sin (e+f x))}{a^2 f}-\frac{10 \tan (e+f x) \left (c^3-c^3 \sec (e+f x)\right )}{3 f \left (a^2 \sec (e+f x)+a^2\right )}+\frac{2 c \tan (e+f x) (c-c \sec (e+f x))^2}{3 f (a \sec (e+f x)+a)^2} \]
Antiderivative was successfully verified.
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Rule 3957
Rule 3787
Rule 3770
Rule 3767
Rule 8
Rubi steps
\begin{align*} \int \frac{\sec (e+f x) (c-c \sec (e+f x))^3}{(a+a \sec (e+f x))^2} \, dx &=\frac{2 c (c-c \sec (e+f x))^2 \tan (e+f x)}{3 f (a+a \sec (e+f x))^2}-\frac{(5 c) \int \frac{\sec (e+f x) (c-c \sec (e+f x))^2}{a+a \sec (e+f x)} \, dx}{3 a}\\ &=\frac{2 c (c-c \sec (e+f x))^2 \tan (e+f x)}{3 f (a+a \sec (e+f x))^2}-\frac{10 \left (c^3-c^3 \sec (e+f x)\right ) \tan (e+f x)}{3 f \left (a^2+a^2 \sec (e+f x)\right )}+\frac{\left (5 c^2\right ) \int \sec (e+f x) (c-c \sec (e+f x)) \, dx}{a^2}\\ &=\frac{2 c (c-c \sec (e+f x))^2 \tan (e+f x)}{3 f (a+a \sec (e+f x))^2}-\frac{10 \left (c^3-c^3 \sec (e+f x)\right ) \tan (e+f x)}{3 f \left (a^2+a^2 \sec (e+f x)\right )}+\frac{\left (5 c^3\right ) \int \sec (e+f x) \, dx}{a^2}-\frac{\left (5 c^3\right ) \int \sec ^2(e+f x) \, dx}{a^2}\\ &=\frac{5 c^3 \tanh ^{-1}(\sin (e+f x))}{a^2 f}+\frac{2 c (c-c \sec (e+f x))^2 \tan (e+f x)}{3 f (a+a \sec (e+f x))^2}-\frac{10 \left (c^3-c^3 \sec (e+f x)\right ) \tan (e+f x)}{3 f \left (a^2+a^2 \sec (e+f x)\right )}+\frac{\left (5 c^3\right ) \operatorname{Subst}(\int 1 \, dx,x,-\tan (e+f x))}{a^2 f}\\ &=\frac{5 c^3 \tanh ^{-1}(\sin (e+f x))}{a^2 f}-\frac{5 c^3 \tan (e+f x)}{a^2 f}+\frac{2 c (c-c \sec (e+f x))^2 \tan (e+f x)}{3 f (a+a \sec (e+f x))^2}-\frac{10 \left (c^3-c^3 \sec (e+f x)\right ) \tan (e+f x)}{3 f \left (a^2+a^2 \sec (e+f x)\right )}\\ \end{align*}
Mathematica [B] time = 4.25574, size = 485, normalized size = 4.08 \[ \frac{c^3 (\cos (e+f x)-1)^3 \cot \left (\frac{1}{2} (e+f x)\right ) \csc ^2\left (\frac{1}{2} (e+f x)\right ) \left (-\frac{1}{16} \sec ^3\left (\frac{e}{2}\right ) \sin \left (\frac{f x}{2}\right ) (-80 \cos (e+f x)-40 \cos (2 (e+f x))+66 \cos (2 e+f x)+23 \cos (e+2 f x)+17 \cos (3 e+2 f x)+40 \cos (e)+78 \cos (f x)-40) \csc ^5\left (\frac{1}{2} (e+f x)\right )-26 \sec \left (\frac{e}{2}\right ) \sin \left (\frac{f x}{2}\right ) \cot ^4\left (\frac{1}{2} (e+f x)\right ) \csc \left (\frac{1}{2} (e+f x)\right )+20 \sec \left (\frac{e}{2}\right ) \sin \left (\frac{f x}{2}\right ) \cot ^2\left (\frac{1}{2} (e+f x)\right ) \csc \left (\frac{1}{2} (e+f x)\right )+2 \left (\sin \left (\frac{3 e}{2}\right )-\sin \left (\frac{e}{2}\right )\right ) \sec ^3\left (\frac{e}{2}\right ) \cot \left (\frac{1}{2} (e+f x)\right ) \csc ^2\left (\frac{1}{2} (e+f x)\right )-15 \cos (e) \sec ^2\left (\frac{e}{2}\right ) \cot ^5\left (\frac{1}{2} (e+f x)\right ) \left (\log \left (\cos \left (\frac{1}{2} (e+f x)\right )-\sin \left (\frac{1}{2} (e+f x)\right )\right )-\log \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )\right )-\left (\tan ^2\left (\frac{e}{2}\right )-1\right ) \cot ^3\left (\frac{1}{2} (e+f x)\right ) \left (15 \left (\log \left (\cos \left (\frac{1}{2} (e+f x)\right )-\sin \left (\frac{1}{2} (e+f x)\right )\right )-\log \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )\right )-4 \tan \left (\frac{e}{2}\right ) \csc ^2\left (\frac{1}{2} (e+f x)\right )\right )\right )}{6 a^2 f \left (\tan \left (\frac{e}{2}\right )-1\right ) \left (\tan \left (\frac{e}{2}\right )+1\right ) (\cos (e+f x)+1)^2 \left (\cot \left (\frac{1}{2} (e+f x)\right )-1\right ) \left (\cot \left (\frac{1}{2} (e+f x)\right )+1\right )} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.074, size = 136, normalized size = 1.1 \begin{align*} -{\frac{4\,{c}^{3}}{3\,f{a}^{2}} \left ( \tan \left ({\frac{fx}{2}}+{\frac{e}{2}} \right ) \right ) ^{3}}-8\,{\frac{{c}^{3}\tan \left ( 1/2\,fx+e/2 \right ) }{f{a}^{2}}}+{\frac{{c}^{3}}{f{a}^{2}} \left ( \tan \left ({\frac{fx}{2}}+{\frac{e}{2}} \right ) +1 \right ) ^{-1}}+5\,{\frac{{c}^{3}\ln \left ( \tan \left ( 1/2\,fx+e/2 \right ) +1 \right ) }{f{a}^{2}}}+{\frac{{c}^{3}}{f{a}^{2}} \left ( \tan \left ({\frac{fx}{2}}+{\frac{e}{2}} \right ) -1 \right ) ^{-1}}-5\,{\frac{{c}^{3}\ln \left ( \tan \left ( 1/2\,fx+e/2 \right ) -1 \right ) }{f{a}^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.01091, size = 460, normalized size = 3.87 \begin{align*} -\frac{c^{3}{\left (\frac{\frac{15 \, \sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} + \frac{\sin \left (f x + e\right )^{3}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{3}}}{a^{2}} - \frac{12 \, \log \left (\frac{\sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} + 1\right )}{a^{2}} + \frac{12 \, \log \left (\frac{\sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} - 1\right )}{a^{2}} + \frac{12 \, \sin \left (f x + e\right )}{{\left (a^{2} - \frac{a^{2} \sin \left (f x + e\right )^{2}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{2}}\right )}{\left (\cos \left (f x + e\right ) + 1\right )}}\right )} + 3 \, c^{3}{\left (\frac{\frac{9 \, \sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} + \frac{\sin \left (f x + e\right )^{3}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{3}}}{a^{2}} - \frac{6 \, \log \left (\frac{\sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} + 1\right )}{a^{2}} + \frac{6 \, \log \left (\frac{\sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} - 1\right )}{a^{2}}\right )} + \frac{3 \, c^{3}{\left (\frac{3 \, \sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} + \frac{\sin \left (f x + e\right )^{3}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{3}}\right )}}{a^{2}} - \frac{c^{3}{\left (\frac{3 \, \sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} - \frac{\sin \left (f x + e\right )^{3}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{3}}\right )}}{a^{2}}}{6 \, f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.484874, size = 440, normalized size = 3.7 \begin{align*} \frac{15 \,{\left (c^{3} \cos \left (f x + e\right )^{3} + 2 \, c^{3} \cos \left (f x + e\right )^{2} + c^{3} \cos \left (f x + e\right )\right )} \log \left (\sin \left (f x + e\right ) + 1\right ) - 15 \,{\left (c^{3} \cos \left (f x + e\right )^{3} + 2 \, c^{3} \cos \left (f x + e\right )^{2} + c^{3} \cos \left (f x + e\right )\right )} \log \left (-\sin \left (f x + e\right ) + 1\right ) - 2 \,{\left (23 \, c^{3} \cos \left (f x + e\right )^{2} + 34 \, c^{3} \cos \left (f x + e\right ) + 3 \, c^{3}\right )} \sin \left (f x + e\right )}{6 \,{\left (a^{2} f \cos \left (f x + e\right )^{3} + 2 \, a^{2} f \cos \left (f x + e\right )^{2} + a^{2} f \cos \left (f x + e\right )\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} - \frac{c^{3} \left (\int - \frac{\sec{\left (e + f x \right )}}{\sec ^{2}{\left (e + f x \right )} + 2 \sec{\left (e + f x \right )} + 1}\, dx + \int \frac{3 \sec ^{2}{\left (e + f x \right )}}{\sec ^{2}{\left (e + f x \right )} + 2 \sec{\left (e + f x \right )} + 1}\, dx + \int - \frac{3 \sec ^{3}{\left (e + f x \right )}}{\sec ^{2}{\left (e + f x \right )} + 2 \sec{\left (e + f x \right )} + 1}\, dx + \int \frac{\sec ^{4}{\left (e + f x \right )}}{\sec ^{2}{\left (e + f x \right )} + 2 \sec{\left (e + f x \right )} + 1}\, dx\right )}{a^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.3827, size = 171, normalized size = 1.44 \begin{align*} \frac{\frac{15 \, c^{3} \log \left ({\left | \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right ) + 1 \right |}\right )}{a^{2}} - \frac{15 \, c^{3} \log \left ({\left | \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right ) - 1 \right |}\right )}{a^{2}} + \frac{6 \, c^{3} \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )}{{\left (\tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )^{2} - 1\right )} a^{2}} - \frac{4 \,{\left (a^{4} c^{3} \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )^{3} + 6 \, a^{4} c^{3} \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )\right )}}{a^{6}}}{3 \, f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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